Test Series - w Quants

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Test Number 14/24

Q: If X is a prime number, LCM of X and its successive number would be
A. X/(X+1)
B. (X+1)
C. X (X+1)
D. X
Solution: X (X+1)
Q: If the amount received at the end of 2nd and 3rd year at Compound Interest on a certain Principal is Rs 32448 and Rs 33745.92 respectively, what is the rate of interest?
A. 2 percent
B. 8 percent
C. 4 percent
D. 6 percent
Solution: 4 percent
Q: A man invests Rs.5000 for 3 years at 5% p.a. compound interest reckoned yearly. Income tax at the rate of 20% on the interest earned is deducted at the end of each year. Find the amount at the end of the third year
A. Rs.5423
B. Rs.5634
C. Rs.5624.32
D. Rs.5976
Solution: 5% is the rate of interest. 20% of the interest amount is paid as tax.
 
i.e  80% of the interest amount stays back.
 
 if we compute the rate of interest as 80% of 5% = 4% p.a., we will get the same value.
  
The interest accrued for 3 years in compound interest = 3 x simple interest on principal + 3 x interest on simple interest + 1 x interest on interest on interest.
 
= 3 x (200) + 3 x (8) + 1 x 0.32 =600 + 24 + 0.32 = 624.32
The amount at the end of 3 years = 5000 + 624.32 = 5624.32
Q: Mr. Ibrahim borrowed Rs. 7500 at 5% per annum compound interest. The compound interest compounded annually for 2 years is
A. 786.75
B. 8268.75
C. 768.75
D. 8286.75
Solution: 8268.75
Q: If 47. 2506 = 4*A + 7/B + 2*C + 5/D + 6*E, then the value of 5*A + 3*B + 6*C + D + 3*E is :
A. 213.003
B. 53.603
C. 153.6003
D. 55.6003
Solution: 4*A + 7/B + 2*C + 5/D + 6*E =47.2506 => 4 * A + 7/B + 2 *C + 5/D + 6*E = 40 + 7 + 0.2 + 0.05 + 0.0006 Comparing the terms on both sides, we get : 4*A =40, 7/B = 7, 2*C = 0.2, 5/D = 0.05, 6*E = 0.0006 A = 10, B = 1, C = 0.1, D = 100, E = 0.0001. 5*A + 3*B + 6*C + D + 3*E =(5*10) + (3*1) + (6*0.1) +100 +(3*0.0001) =50 + 3 + 0.6 + 100 + 0.003 = 153.6003.
Q: A person was asked to state his age in years. His reply was , "Take my age 3 years hence, multiply it by 3 and subtract 3 times my age 3 years ago and you will know how old I am." What was the age of the person ?
A. 24
B. 18
C. 30
D. 20
Solution: Let the present age of person be   x years.
Then, 3(x + 3) - 3(x - 3 ) = x   <=> (3x + 9) - (3x - 9) = x  <=> x = 18.
Q: The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years, The ratio of the number of boys to the number of girls in the class is :
A. 1 : 2
B. 3 : 4
C. 4 : 5
D. 2 : 3
Solution:  Let the ratio be k : 1. Then,
k * 16.4 + 1 * 15.4 = (k + 1) * 15.8 <=> (16.4 - 15.8) k = (15.8 - 15.4)  <=> k =  0.4/0.6 = 2/3.
Required ratio  = 2/3 : 1 = 2 : 3.
Q: David obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?
A. 65
B. 68
C. 75
D. 60
Solution: Average =   (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5   =  75.
Q: A family consists of grandparents, parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family ?
A. 34(4/7)
B. 35(4/9)
C. 32 (6/7)
D. 31( 5/7)
Solution: Required average = (67 * 2 + 35 * 2 + 6 * 3) / (2 + 2 + 3)
                           = (134 + 70 + 18) / 7  =  222 / 7 = 31(5/7) years.

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